(2x^2+10)/(x-2)

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Solution for (2x^2+10)/(x-2) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(2*x^2+10)/(x-2) = 0

2*x^2 = -10 // : 2

x^2 = -5

x belongs to the empty set

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